(9x^2-6x+1)*(3x+2)=0

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Solution for (9x^2-6x+1)*(3x+2)=0 equation:


Simplifying
(9x2 + -6x + 1)(3x + 2) = 0

Reorder the terms:
(1 + -6x + 9x2)(3x + 2) = 0

Reorder the terms:
(1 + -6x + 9x2)(2 + 3x) = 0

Multiply (1 + -6x + 9x2) * (2 + 3x)
(1(2 + 3x) + -6x * (2 + 3x) + 9x2 * (2 + 3x)) = 0
((2 * 1 + 3x * 1) + -6x * (2 + 3x) + 9x2 * (2 + 3x)) = 0
((2 + 3x) + -6x * (2 + 3x) + 9x2 * (2 + 3x)) = 0
(2 + 3x + (2 * -6x + 3x * -6x) + 9x2 * (2 + 3x)) = 0
(2 + 3x + (-12x + -18x2) + 9x2 * (2 + 3x)) = 0
(2 + 3x + -12x + -18x2 + (2 * 9x2 + 3x * 9x2)) = 0
(2 + 3x + -12x + -18x2 + (18x2 + 27x3)) = 0

Combine like terms: 3x + -12x = -9x
(2 + -9x + -18x2 + 18x2 + 27x3) = 0

Combine like terms: -18x2 + 18x2 = 0
(2 + -9x + 0 + 27x3) = 0
(2 + -9x + 27x3) = 0

Solving
2 + -9x + 27x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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